BTI's Rants and Ramblings: Repeat Matchups in the Final Four Look to Favor Kentucky

Bryan the Internover 6 years


Aritcle written by:Bryan the InternBryan the Intern
I've heard this stat mentioned many times on television that the meeting between Kentucky and Wisconsin is just the 3rd time in NCAA history where 2 teams have met in the national semifinals in consecutive years.  That is a correct stat as it happened in 1959-60 and in 1961-62.  In both of those instances, the same team won both games.  I thought I would stretch it out even further to any time 2 teams met in the Final Four (semis or finals) in consecutive years, and you find that has happened a total of 5 times:
1959: California 64, Cincinnati 58 1960: California 77, Cincinnati 69 1961: Cincinnati 70, Ohio State 65 1962: Cincinnati 71, Ohio State 59 1967: UCLA 73, Houston 58 1968: UCLA 101, Houston 69 1990: UNLV 103, Duke 73 1991: Duke 79, UNLV 77 2006: Florida 73, UCLA 57 2007: Florida 76, UCLA 66 In 4 of the 5 occasions, the same team has won both games.  And consider in 3 of those 4 instances, the 2nd meeting between the 2 teams resulted in a greater margin of victory than the first time.  What this shows to me is a couple things.  First of all, revenge games don't exist over the course of 2 seasons.  By that time, some of players have changed and I am sure the sting of the loss has worn off much more than when it occurs in the same season.  Secondly, more often than not the better team wins.  In all of the cases above (sans Duke-UNLV) the better team won both matchups.  There were no upsets there.  Kentucky, on paper, is the better team.  History shows us that UK fans should feel quite confident going into Saturday.

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