Numerical sports question for you math genius....

[99jc]

Whats the formula to calculate how many outcomes are their for a 10 parlay bet?

 

[dawgstudent]

10*9*8*7.......until you get to 1 which is 3628800 outcomes. Could be completely wrong.

 

[8dog]

one where order matters and one where it doesn't. This would be the latter.

Yours could well be right.

 

[birdZdawg]

but each game has 3 possible outcomes based on the spread. Win, lose, or push. For 10 games, that would be 3 to the 10th power, or 59,049 possible outcomes.

 

[Coastdog28]

I think you can say 0.5^10. Assuming each game is a coinflip, multiply the 50% by itself the number of times of games you have. It comes out to around a .1% chance of getting it. Or a 1 in 1000 chance.

 

[patdog]

Not as bad as dawgstudent's scenario, but still not good.</p>

 

[RobbieRandolph]

But a push is just dropped off of a parlay bet. So a push in 1 game would drop it to a 9-game parlay. Discounting a push as a possible result to the bet since it doesn't affect the outcome of the total parlay result, just the payout, it's just 2 to the 10th, or 1024.

 

[Coastdog28]

Also the odds of a push are not 33%. They are very very low.

 

[Coastdog28]

Just two different ways.

 

[Purebred Dawg]

Maybe they can help. Nerds!</p>

 

[Jack At Shelter]

Another way to look at it:

1 way for losing all, and 1 for winning all
10 ways to win 1, and 10 ways to win 9
45 ways to win 2, and 45 ways to win 8
120 ways to win 3, and 120 ways to win 7
210 ways to win 4, and 210 ways to win 6
252 ways to win 5

Grand total of 1024